programming

How do I call a remote plist for use in my application?

I have added my first php page to add a dynamic page but need to display the results of a my sql query in different sections.

For a menu to link to its own page and display a summary of each seperatly on the page.

Does PHP have functions for GetYear, GetMonth, & GetDay

example:
$Date = 2009-8-7;
$Year = GetYear($Date);
print $Year;//print 2009
and so on . . .

I have a query that never returns any results or errors. When I run the sql directly through phpmyadmin the results come back fine.

just trying to dump row right now to see whats coming back

I'm just starting php and test page was working but now getting
Warning: session_start() [function.session-start]: Cannot send session cookie

I just made some minor edits and now its not working.

I'm helping someone with an old someone else made admin program to add / edit / delete records

Some of the people working on it are always pressing the back and forward button and reposting the info multiple times. Is there a way keep this from happening?

not the real code but close enough

The addrecord.php page

<?
include_once('dataconnection.php');
$title=$_POST['title'];
more fields
.
.
.

I'm successfully connecting to a mssql database and getting results, but I'm trying to place them in an array for display on the page.

The following always gets 1 result and nothing more.
I thought arrays are supposed to store multiple results?

<?php

$conn=odbc_connect('*****','******','*****');
if (!$conn)
{exit("Connection Failed: " . $conn);}

$sql="select Name,Id,Group from members";
$rs=odbc_exec($conn,$sql);
if (!$rs)
{exit("Error in SQL");
echo '';

while (odbc_fetch_row($rs))
{
$id=odbc_result($rs,"Id");

I have a form that only has one field for name and I want to get the two values submitted and store first and last as seperate values in the database. How would I do that?